: ( E = P \cdot t ) (Joules or kWh)
$$\lambda = c \times T = \fraccf$$
: ( N = n \cdot N_A ) ( N_A = 6.022 \times 10^23 , \textmol^-1 ) (Avogadro’s number)
: ( E = P \cdot t ) (Joules or kWh)
$$\lambda = c \times T = \fraccf$$
: ( N = n \cdot N_A ) ( N_A = 6.022 \times 10^23 , \textmol^-1 ) (Avogadro’s number) formule de physique chimie