Integral Topic Assessment Answers Jun 2026

$$∫[0,2] (2x - x^2)dx = [x^2 - \fracx^33]_0^2 = (2^2 - \frac2^33) - (0^2 - \frac0^33) = 4 - \frac83 = \frac43$$

The upper curve is y = 2x, and the lower curve is y = x^2. integral topic assessment answers

Integrals are a fundamental concept in calculus, which is a branch of mathematics that deals with the study of continuous change. In essence, an integral is used to find the area under a curve or the accumulation of a quantity over a defined interval. It's a crucial tool for solving problems in physics, engineering, economics, and other fields. $$∫[0,2] (2x - x^2)dx = [x^2 - \fracx^33]_0^2

Answer: [x^2 + x] from 0 to 2 = (2^2 + 2) - (0^2 + 0) = 6 integral topic assessment answers